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1.
Algorithm, Formulas, Examples added
on 20.07.18
2.
Simplex method Algorithm and examples
on 08.07.18
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Graphical method calculator
** check different types of Graphical method examples
Algorithm and examples
*Subtraction Steps display option is added for calculation steps, if required(on 21-Jul-18).
Solve the Linear programming problem using
Graphical method calculator
Type your linear programming problem
OR
Total Variables :
Total Constraints :
Click On Generate
Mode :
Fraction
Decimal
Solve after converting Min function to Max function
Zj-Cj (display in steps)
Alternate Solution (if exists)
Artificial Column Remove
Subtraction Steps
Tooltip for calculation steps
Highlight dependent cells
Find
1. Simplex (BigM) method
2. TwoPhase method
3. Dual simplex method
4. Integer simplex method
5. Graphical method
6. Primal to Dual
7. Branch and Bound method
8. 0-1 Integer programming problem
max z = -2x1 - x2
subject to
-3x1 - x2 <= -3
-4x1 - 3x2 <= -6
-x1 - 2x2 <= -3
and x1,x2 >= 0
max z = 15x1 + 10x2
subject to
4x1 + 6x2 <= 360
3x1 <= 180
5x2 <= 200
and x1,x2 >= 0
max z = 2x1 + x2
subject to
x1 + 2x2 <= 10
x1 + x2 <= 6
x1 - x2 <= 2
x1 - 2x2 <= 1
and x1,x2 >= 0
max z = -x1 + 2x2
subject to
x1 - x2 <= -1
-0.5x1 + x2 <= 2
and x1,x2 >= 0
max z = 40x1 + 80x2
subject to
2x1 + 3x2 <= 48
x1 <= 15
x2 <= 10
and x1,x2 >= 0
max z = 60x1 + 40x2
subject to
x1 <= 25
x2 <= 35
2x1 + x2 <= 60
and x1,x2 >= 0
min z = 3x1 + 2x2
subject to
5x1 + x2 >= 10
x1 + x2 >= 6
x1 + 4x2 >= 12
and x1,x2 >= 0
min z = 600x1 + 400x2
subject to
3x1 + 3x2 >= 40
3x1 + x2 >= 40
2x1 + 5x2 >= 44
and x1,x2 >= 0
min z = 4x1 + 3x2
subject to
200x1 + 100x2 >= 4000
x1 + 2x2 >= 50
40x1 + 40x2 >= 1400
and x1,x2 >= 0
min z = -x1 + 2x2
subject to
-x1 + 3x2 <= 10
x1 + x2 <= 6
x1 - x2 <= 2
and x1,x2 >= 0
max z = -15x1 - 10x2
subject to
-3x1 - 5x2 <= -5
-5x1 - 2x2 <= -3
and x1,x2 >= 0
max z = 600x1 + 500x2
subject to
2x1 + x2 >= 80
x1 + 2x2 >= 60
and x1,x2 >= 0
max z = 3x1 + 2x2
subject to
x1 - x2 >= 1
x1 + x2 >= 3
and x1,x2 >= 0
max z = 5x1 + 4x2
subject to
x1 - 2x2 <= 1
x1 + 2x2 >= 3
and x1,x2 >= 0
max z = -4x1 + 3x2
subject to
x1 - x2 <= 0
x1 <= 4
and x1,x2 >= 0
max z = 3x1 + 4x2
subject to
x1 - x2 = -1
-x1 + x2 <= 0
and x1,x2 >= 0
max z = 6x1 - 4x2
subject to
2x1 + 4x2 <= 4
4x1 + 8x2 >= 16
and x1,x2 >= 0
max z = x1 + 1/2x2
subject to
3x1 + 2x2 <= 12
5x1 = 10
x1 + x2 >= 8
-x1 + x2 >= 4
and x1,x2 >= 0
max z = 3x1 + 2x2
subject to
-2x1 + 3x2 <= 9
3x1 - 2x2 <= -20
and x1,x2 >= 0
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