

*New code written for removing artificial column from Iteration table (on 17Sep17).
It may be possible, some working problem may not work properly. If you find any such problem then mail me immediately with the problem, so i will try my best to improve the software as soon as possible.

Solve the Linear programming problem using
Graphical method

Type your linear programming problem


OR

Total Variables :
Total Constraints :



Click On Generate


Mode :



Find


 max z = 2x1  x2
subject to 3x1  x2 <= 3 4x1  3x2 <= 6 x1  2x2 <= 3 and x1,x2 >= 0
 max z = 15x1 + 10x2
subject to 4x1 + 6x2 <= 360 3x1 <= 180 5x2 <= 200 and x1,x2 >= 0
 max z = 2x1 + x2
subject to x1 + 2x2 <= 10 x1 + x2 <= 6 x1  x2 <= 2 x1  2x2 <= 1 and x1,x2 >= 0
 max z = x1 + 2x2
subject to x1  x2 <= 1 0.5x1 + x2 <= 2 and x1,x2 >= 0
 max z = 40x1 + 80x2
subject to 2x1 + 3x2 <= 48 x1 <= 15 x2 <= 10 and x1,x2 >= 0
 max z = 60x1 + 40x2
subject to x1 <= 25 x2 <= 35 2x1 + x2 <= 60 and x1,x2 >= 0
 min z = 3x1 + 2x2
subject to 5x1 + x2 >= 10 x1 + x2 >= 6 x1 + 4x2 >= 12 and x1,x2 >= 0
 min z = 600x1 + 400x2
subject to 3x1 + 3x2 >= 40 3x1 + x2 >= 40 2x1 + 5x2 >= 44 and x1,x2 >= 0
 min z = 4x1 + 3x2
subject to 200x1 + 100x2 >= 4000 x1 + 2x2 >= 50 40x1 + 40x2 >= 1400 and x1,x2 >= 0
 min z = x1 + 2x2
subject to x1 + 3x2 <= 10 x1 + x2 <= 6 x1  x2 <= 2 and x1,x2 >= 0
 max z = 15x1  10x2
subject to 3x1  5x2 <= 5 5x1  2x2 <= 3 and x1,x2 >= 0
 max z = 600x1 + 500x2
subject to 2x1 + x2 >= 80 x1 + 2x2 >= 60 and x1,x2 >= 0
 max z = 3x1 + 2x2
subject to x1  x2 >= 1 x1 + x2 >= 3 and x1,x2 >= 0
 max z = 5x1 + 4x2
subject to x1  2x2 <= 1 x1 + 2x2 >= 3 and x1,x2 >= 0
 max z = 4x1 + 3x2
subject to x1  x2 <= 0 x1 <= 4 and x1,x2 >= 0
 max z = 3x1 + 4x2
subject to x1  x2 = 1 x1 + x2 <= 0 and x1,x2 >= 0
 max z = 6x1  4x2
subject to 2x1 + 4x2 <= 4 4x1 + 8x2 >= 16 and x1,x2 >= 0
 max z = x1 + 1/2x2
subject to 3x1 + 2x2 <= 12 5x1 = 10 x1 + x2 >= 8 x1 + x2 >= 4 and x1,x2 >= 0
 max z = 3x1 + 2x2
subject to 2x1 + 3x2 <= 9 3x1  2x2 <= 20 and x1,x2 >= 0





Solution 


Share with Your Friends :

Solve the following LP problem
using Graphical method





