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Primal to dual conversion calculator
16.05.18 - Dual simplex method new implementation(1. infeasible solution and 2. fails to get solution)
Solve the Linear programming problem using
Primal to dual conversion calculator
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OR
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Total Constraints :
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Solve after converting Min function to Max function
Zj-Cj (display in steps)
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1. Simplex (BigM) method
2. TwoPhase method
3. Dual simplex method
4. Integer simplex method
5. Graphical method
6. Primal to Dual
7. Branch and Bound method
8. 0-1 Integer programming problem
max z = x1 - x2 + 3x3
subject to
x1 + x2 + x3 <= 10
2x1 - x2 - x3 <= 2
2x1 - 2x2 - 3x3 <= 6
and x1,x2,x3 >= 0
min z = 3x1 - 2x2 + 4x3
subject to
3x1 + 5x2 + 4x3 >= 7
6x1 + x2 + 3x3 >= 4
7x1 - 2x2 - x3 <= 10
x1 - 2x2 + 5x3 >= 3
4x1 + 7x2 - 2x3 >= 2
and x1,x2,x3 >= 0
min z = x1 + 2x2
subject to
2x1 + 4x2 <= 160
x1 - x2 = 30
x1 >= 10
and x1,x2 >= 0
min z = x1 - 3x2 - 2x3
subject to
3x1 - x2 + 2x3 <= 7
2x1 - 4x2 >= 12
-4x1 + 3x2 + 8x3 = 10
and x1,x2 >= 0 and x3 unrestricted in sign
max z = x1 - 2x2 + 3x3
subject to
-2x1 + x2 + 3x3 = 2
2x1 + 3x2 + 4x3 = 1
and x1,x2,x3 >= 0
max z = 3x1 + x2 + 2x3 - x4
subject to
2x1 - x2 + 3x3 + x4 = 1
x1 + x2 - x3 + x4 = 3
and x1,x2 >= 0 and x3,x4 unrestricted in sign
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Primal to dual
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Solve the following LP problem using Primal to dual conversion calculator
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