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1.
Algorithm, Formulas, Examples added
on 20.07.18
2.
Simplex method Algorithm and examples
on 08.07.18
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Simplex method calculator
** check different types of Simplex method examples
Algorithm and examples
*Subtraction Steps display option is added for calculation steps, if required(on 21-Jul-18).
Solve the Linear programming problem using
Simplex method calculator
Type your linear programming problem
OR
Total Variables :
Total Constraints :
Click On Generate
Mode :
Fraction
Decimal
Solve after converting Min function to Max function
Zj-Cj (display in steps)
Alternate Solution (if exists)
Artificial Column Remove
Subtraction Steps
Tooltip for calculation steps
Highlight dependent cells
Find
1. Simplex (BigM) method
2. TwoPhase method
3. Dual simplex method
4. Integer simplex method
5. Graphical method
6. Primal to Dual
7. Branch and Bound method
8. 0-1 Integer programming problem
max Z = 3x1 + 5x2 + 4x3
subject to
2x1 + 3x2 <= 8
2x2 + 5x3 <= 10
3x1 + 2x2 + 4x3 <= 15
and x1,x2,x3 >= 0
max Z = 5x1 + 10x2 + 8x3
subject to
3x1 + 5x2 + 2x3 <= 60
4x1 + 4x2 + 4x3 <= 72
2x1 + 4x2 + 5x3 <= 100
and x1,x2,x3 >= 0
max Z = 4x1 + 3x2
subject to
2x1 + x2 <= 1000
x1 + x2 <= 800
x1 <= 400
x2 <= 700
and x1,x2 >= 0
min Z = x1 + x2
subject to
2x1 + 4x2 >= 4
x1 + 7x2 >= 7
and x1,x2 >= 0
min Z = 600x1 + 500x2
subject to
2x1 + x2 >= 80
x1 + 2x2 >= 60
and x1,x2 >= 0
min Z = 5x1 + 3x2
subject to
2x1 + 4x2 <= 12
2x1 + 2x2 = 10
5x1 + 2x2 >= 10
and x1,x2 >= 0
max Z = x1 + 2x2 + 3x3 - x4
subject to
x1 + 2x2 + 3x3 = 15
2x1 + x2 + 5x3 = 20
x1 + 2x2 + x3 + x4 = 10
and x1,x2,x3,x4 >= 0
max Z = 3x1 + 9x2
subject to
x1 + 4x2 <= 8
x1 + 2x2 <= 4
and x1,x2 >= 0
max Z = 3x1 + 2x2 + x3
subject to
2x1 + 5x2 + x3 = 12
3x1 + 4x2 = 11
and x2,x3 >= 0 and x1 unrestricted in sign
max Z = 3x1 + 3x2 + 2x3 + x4
subject to
2x1 + 2x2 + 5x3 + x4 = 12
3x1 + 3x2 + 4x3 = 11
and x1,x2,x3,x4 >= 0
max Z = 6x1 + 4x2
subject to
2x1 + 3x2 <= 30
3x1 + 2x2 <= 24
x1 + x2 >= 3
and x1,x2 >= 0
max Z = 3x1 + 5x2
subject to
x1 - 2x2 <= 6
x1 <= 10
x2 >= 1
and x1,x2 >= 0
max Z = 6x1 + 4x2
subject to
x1 + x2 <= 5
x2 >= 8
and x1,x2 >= 0
max Z = 6x1 + 4x2
subject to
-x1 - x2 >= -5
x2 >= 8
and x1,x2 >= 0
Solution
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