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Simplex method calculator
16.05.18 - Dual simplex method new implementation(1. infeasible solution and 2. fails to get solution)
Solve the Linear programming problem using
Simplex method calculator
Type your linear programming problem
OR
Total Variables :
Total Constraints :
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Mode :
Fraction
Decimal
Solve after converting Min function to Max function
Zj-Cj (display in steps)
Alternate Solution (if exists)
Artificial Column Remove
Tooltip for calculation steps
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1. Simplex (BigM) method
2. TwoPhase method
3. Dual simplex method
4. Integer simplex method
5. Graphical method
6. Primal to Dual
7. Branch and Bound method
8. 0-1 Integer programming problem
max Z = 3x1 + 5x2 + 4x3
subject to
2x1 + 3x2 <= 8
2x2 + 5x3 <= 10
3x1 + 2x2 + 4x3 <= 15
and x1,x2,x3 >= 0
max Z = 5x1 + 10x2 + 8x3
subject to
3x1 + 5x2 + 2x3 <= 60
4x1 + 4x2 + 4x3 <= 72
2x1 + 4x2 + 5x3 <= 100
and x1,x2,x3 >= 0
max Z = 4x1 + 3x2
subject to
2x1 + x2 <= 1000
x1 + x2 <= 800
x1 <= 400
x2 <= 700
and x1,x2 >= 0
min Z = x1 + x2
subject to
2x1 + 4x2 >= 4
x1 + 7x2 >= 7
and x1,x2 >= 0
min Z = 600x1 + 500x2
subject to
2x1 + x2 >= 80
x1 + 2x2 >= 60
and x1,x2 >= 0
min Z = 5x1 + 3x2
subject to
2x1 + 4x2 <= 12
2x1 + 2x2 = 10
5x1 + 2x2 >= 10
and x1,x2 >= 0
max Z = x1 + 2x2 + 3x3 - x4
subject to
x1 + 2x2 + 3x3 = 15
2x1 + x2 + 5x3 = 20
x1 + 2x2 + x3 + x4 = 10
and x1,x2,x3,x4 >= 0
max Z = 3x1 + 9x2
subject to
x1 + 4x2 <= 8
x1 + 2x2 <= 4
and x1,x2 >= 0
max Z = 3x1 + 2x2 + x3
subject to
2x1 + 5x2 + x3 = 12
3x1 + 4x2 = 11
and x2,x3 >= 0 and x1 unrestricted in sign
max Z = 3x1 + 3x2 + 2x3 + x4
subject to
2x1 + 2x2 + 5x3 + x4 = 12
3x1 + 3x2 + 4x3 = 11
and x1,x2,x3,x4 >= 0
max Z = 6x1 + 4x2
subject to
2x1 + 3x2 <= 30
3x1 + 2x2 <= 24
x1 + x2 >= 3
and x1,x2 >= 0
max Z = 3x1 + 5x2
subject to
x1 - 2x2 <= 6
x1 <= 10
x2 >= 1
and x1,x2 >= 0
max Z = 6x1 + 4x2
subject to
x1 + x2 <= 5
x2 >= 8
and x1,x2 >= 0
max Z = 6x1 + 4x2
subject to
-x1 - x2 >= -5
x2 >= 8
and x1,x2 >= 0
Solution
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Simplex Method
BigM Method
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