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5. Calculus method example ( Enter your problem )
  1. Method & Example-1
  2. Example-2
Other related methods
  1. Saddle point
  2. Dominance method
  3. Oddment method
  4. Algebraic method
  5. Calculus method
  6. Arithmetic method
  7. Matrix method
  8. 2Xn Games
  9. Graphical method
  10. Linear programming method
  11. Bimatrix method

4. Algebraic method
(Previous method)
2. Example-2
(Next example)

1. Method & Example-1





Method
calculus method Steps (Rule)
Step-1: A play's (`p_1`, `p_2`)
`p_1=(d - c)/((a + d) - (b + c))` and `p_2 = 1 - p_1`
Step-2: B play's (`q_1`, `q_2`)
`q_1=(d - b)/((a + d) - (b + c))` and `q_2 = 1 - q_1`
Step-3: Value of the game `V`
`V=a*p_1*q_1+b*p_1*q_2+c*p_2*q_1+d*p_2*q_2`

Example-1
Find Solution of game theory problem using calculus method
Player A\Player BB1B2
A113
A252


Solution:
1. Saddle point testing
Players
Player `B`
`B_1``B_2`
Player `A``A_1` 1  3 
`A_2` 5  2 


We apply the maximin (minimax) principle to analyze the game.

Player `B`
`B_1``B_2`Row
Minimum
Player `A``A_1` 1  (3) `1`
`A_2` 5  [2] `[2]`
Column
Maximum
`5``(3)`


Select minimum from the maximum of columns
Column MiniMax = (3)

Select maximum from the minimum of rows
Row MaxiMin = [2]

Here, Column MiniMax `!=` Row MaxiMin

`:.` This game has no saddle point.



Matrix size is 2`xx`2, so dominance rule is not required.

Solution using calculus method
Here `a=1,b=3,c=5,d=2`

`p_1=(d - c)/((a + d) - (b + c))=(2 -5)/((1 +2) - (3 +5))=(-3)/(3 -8)=3/5`

`p_2=1-p_1=1-3/5=2/5`

`q_1=(d - b)/((a + d) - (b + c))=(2 -3)/((1 +2) - (3 +5))=(-1)/(3 -8)=1/5`

`q_2=1-q_1=1-1/5=4/5`

`V=a*p_1*q_1+b*p_1*q_2+c*p_2*q_1+d*p_2*q_2`

`=1*3/5*1/5 +3*3/5*4/5 +5*2/5*1/5 +2*2/5*4/5`

`=3/25 +36/25 +2/5 +16/25`

`=13/5`


This material is intended as a summary. Use your textbook for detail explanation.
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4. Algebraic method
(Previous method)
2. Example-2
(Next example)





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