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6. Arithmetic method example ( Enter your problem )
  1. Method & Example-1
  2. Example-2

1. Method & Example-1





Method
arithmetic method Steps (Rule)
Step-1: Find the difference between the two values of Row-1 and put this value against the Row-2, ignore the sign.
Step-2: Find the difference between the two values of Row-2 and put this value against the Row-1, ignore the sign.
Step-3: Find the difference between the two values of Column-1 and put this value against the Column-2, ignore the sign.
Step-4: Find the difference between the two values of Column-2 and put this value against the Column-1, ignore the sign.
Step-5: Find probabilities of each by dividing their sum
Step-6: Find value of the game by algebraic method.

Example-1
1. Find Solution of game theory problem using arithmetic method
Player A\Player BB1B2B3
A1105-2
A2131215
A3161410


Solution:
1. Saddle point testing
Players
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 10  5  -2 
`A_2` 13  12  15 
`A_3` 16  14  10 


We apply the maximin (minimax) principle to analyze the game.

Player `B`
`B_1``B_2``B_3`Row
Minimum
Player `A``A_1` 10  5  -2 `-2`
`A_2` 13  [12]  15 `[12]`
`A_3` 16  (14)  10 `10`
Column
Maximum
`16``(14)``15`


Select minimum from the maximum of columns
Column MiniMax = (14)

Select maximum from the minimum of rows
Row MaxiMin = [12]

Here, Column MiniMax `!=` Row MaxiMin

`:.` This game has no saddle point.



2. Dominance rule to reduce the size of the payoff matrix
Using dominance property
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 10  5  -2 
`A_2` 13  12  15 
`A_3` 16  14  10 


row-1 `<=` row-3, so remove row-1

Player `B`
`B_1``B_2``B_3`
Player `A``A_2` 13  12  15 
`A_3` 16  14  10 


column-1 `>=` column-2, so remove column-1

Player `B`
`B_2``B_3`
Player `A``A_2` 12  15 
`A_3` 14  10 




Player `B`
`B_2``B_3`
Player `A``A_2` 12  15 
`A_3` 14  10 


Using arithemetic method to get optimal mixed strategies for both the firms.
Player `B`
`B_2``B_3`
Player `A``A_2` 12  15 `|14-10|=4` `:. p_1=(4)/(3+4)=4/7`
`A_3` 14  10 `|12-15|=3` `:. p_2=(3)/(3+4)=3/7`
`|15-10|=5`
`:. q_1=(5)/(2+5)=5/7`
`|12-14|=2`
`:. q_2=(2)/(2+5)=2/7`


1. Find absolute difference between the two values in the first row and put it against second row of the matrix
`|12-15|=3`

2. Find absolute difference between the two values in the second row and put it against first row of the matrix
`|14-10|=4`

`:. p_1=(4)/(3+4)=4/7`

`:. p_2=(3)/(3+4)=3/7`


3. Find absolute difference between the two values in the first column and put it against second column of the matrix
`|12-14|=2`

4. Find absolute difference between the two values in the second column and put it against first column of the matrix
`|15-10|=5`

`:. q_1=(5)/(2+5)=5/7`

`:. q_2=(2)/(2+5)=2/7`


Hence, firm `A` should adopt strategy `A_2` and `A_3` with 57% of time and 43% of time respectively.

Similarly, firm `B` should adopt strategy `B_2` and `B_3` with 71% of time and 29% of time respectively.


Expected gain of Firm A
`(1)` `12 xx 4/7+14 xx 3/7 = 90/7 ,` Firm `B` adopt `B_2`

`(2)` `15 xx 4/7+10 xx 3/7 = 90/7 ,` Firm `B` adopt `B_3`


Expected loss of Firm B
`(1)` `12 xx 5/7+15 xx 2/7 = 90/7 ,` Firm `A` adopt `A_2`

`(2)` `14 xx 5/7+10 xx 2/7 = 90/7 ,` Firm `A` adopt `A_3`




This material is intended as a summary. Use your textbook for detail explanation.
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