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6. Arithmetic method example ( Enter your problem )
  1. Method & Example-1
  2. Example-2

2. Example-2





Find Solution of game theory problem using arithmetic method
Player A\Player BB1B2B3
A1172
A2627
A3516


Solution:
1. Saddle point testing
Players
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 1  7  2 
`A_2` 6  2  7 
`A_3` 5  1  6 


We apply the maximin (minimax) principle to analyze the game.

Player `B`
`B_1``B_2``B_3`Row
Minimum
Player `A``A_1` 1  7  2 `1`
`A_2` (6)  [2]  7 `[2]`
`A_3` 5  1  6 `1`
Column
Maximum
`(6)``7``7`


Select minimum from the maximum of columns
Column MiniMax = (6)

Select maximum from the minimum of rows
Row MaxiMin = [2]

Here, Column MiniMax `!=` Row MaxiMin

`:.` This game has no saddle point.



2. Dominance rule to reduce the size of the payoff matrix
Using dominance property
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 1  7  2 
`A_2` 6  2  7 
`A_3` 5  1  6 


row-3 `<=` row-2, so remove row-3

Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 1  7  2 
`A_2` 6  2  7 


column-3 `>=` column-1, so remove column-3

Player `B`
`B_1``B_2`
Player `A``A_1` 1  7 
`A_2` 6  2 




reduced matrix
Player `B`
`B_1``B_2`
Player `A``A_1` 1  7 
`A_2` 6  2 


Using arithemetic method to get optimal mixed strategies for both the firms.
Player `B`
`B_1``B_2`
Player `A``A_1` 1  7 `|6-2|=4` `:. p_1=(4)/(6+4)=2/5`
`A_2` 6  2 `|1-7|=6` `:. p_2=(6)/(6+4)=3/5`
`|7-2|=5`
`:. q_1=(5)/(5+5)=1/2`
`|1-6|=5`
`:. q_2=(5)/(5+5)=1/2`


1. Find absolute difference between the two values in the first row and put it against second row of the matrix
`|1-7|=6`

2. Find absolute difference between the two values in the second row and put it against first row of the matrix
`|6-2|=4`

`:. p_1=(4)/(6+4)=2/5`

`:. p_2=(6)/(6+4)=3/5`


3. Find absolute difference between the two values in the first column and put it against second column of the matrix
`|1-6|=5`

4. Find absolute difference between the two values in the second column and put it against first column of the matrix
`|7-2|=5`

`:. q_1=(5)/(5+5)=1/2`

`:. q_2=(5)/(5+5)=1/2`


Hence, firm `A` should adopt strategy `A_1` and `A_2` with 40% of time and 60% of time respectively.

Similarly, firm `B` should adopt strategy `B_1` and `B_2` with 50% of time and 50% of time respectively.


Expected gain of Firm A
`(1)` `1 xx 2/5+6 xx 3/5 = 4 ,` Firm `B` adopt `B_1`

`(2)` `7 xx 2/5+2 xx 3/5 = 4 ,` Firm `B` adopt `B_2`


Expected loss of Firm B
`(1)` `1 xx 1/2+7 xx 1/2 = 4 ,` Firm `A` adopt `A_1`

`(2)` `6 xx 1/2+2 xx 1/2 = 4 ,` Firm `A` adopt `A_2`




This material is intended as a summary. Use your textbook for detail explanation.
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