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7. Matrix method example ( Enter your problem )
  1. Method & Example-1
  2. Example-2

2. Example-2





Find Solution of game theory problem using matrix method
Player A\Player BB1B2B3
A1105-2
A2131215
A3161410


Solution:
1. Saddle point testing
Players
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 10  5  -2 
`A_2` 13  12  15 
`A_3` 16  14  10 


We apply the maximin (minimax) principle to analyze the game.

Player `B`
`B_1``B_2``B_3`Row
Minimum
Player `A``A_1` 10  5  -2 `-2`
`A_2` 13  [12]  15 `[12]`
`A_3` 16  (14)  10 `10`
Column
Maximum
`16``(14)``15`


Select minimum from the maximum of columns
Column MiniMax = (14)

Select maximum from the minimum of rows
Row MaxiMin = [12]

Here, Column MiniMax `!=` Row MaxiMin

`:.` This game has no saddle point.



2. Dominance rule to reduce the size of the payoff matrix
Using dominance property
Player `B`
`B_1``B_2``B_3`
Player `A``A_1` 10  5  -2 
`A_2` 13  12  15 
`A_3` 16  14  10 


row-1 `<=` row-3, so remove row-1

Player `B`
`B_1``B_2``B_3`
Player `A``A_2` 13  12  15 
`A_3` 16  14  10 


column-1 `>=` column-2, so remove column-1

Player `B`
`B_2``B_3`
Player `A``A_2` 12  15 
`A_3` 14  10 




reduced matrix
Player `B`
`B_2``B_3`
Player `A``A_2` 12  15 
`A_3` 14  10 


For this reduced matrix, calculate `P_(Adj)` and `P_(Cof)`

`P_(Adj) = [[10,-15],[-14,12]]`

and `P_(Cof) = [[10,-14],[-15,12]]`

Player A's optimal strategies `=([[1,1]] xx P_(Adj))/([[1,1]] xx P_(Adj) xx [[1],[1]])`

`=([[1,1]][[10,-15],[-14,12]])/([[1,1]][[10,-15],[-14,12]][[1],[1]])`

`=([[-4,-3]])/(-7)`

`=[[4/7,3/7]]`

`p_1=4/7` and `p_2=3/7`, where `p_1` and `p_2` represent the probabilities of player A's, using his strategies `A_2` and `A_3` respectively.


Similarly,
Player B's optimal strategies `=([[1,1]] xx P_(Cof))/([[1,1]] xx P_(Adj) xx [[1],[1]])`

`=([[1,1]][[10,-14],[-15,12]])/([[1,1]][[10,-15],[-14,12]][[1],[1]])`

`=([[-5,-2]])/(-7)`

`=[[5/7,2/7]]`

`q_1=5/7` and `q_2=2/7`, where `q_1` and `q_2` represent the probabilities of player B's, using his strategies `B_2` and `B_3` respectively.


Hence, Value of the game `V` = (Player A's optimal strategies) `xx` (Payoff matrix `P_(ij)`) `xx` (Player B's optimal strategies)

`V=[[4/7,3/7]][[12,15],[14,10]][[5/7],[2/7]]=90/7`




This material is intended as a summary. Use your textbook for detail explanation.
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