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3. Oddment method example ( Enter your problem )
  1. Method & Example-1
  2. Example-2
Other related methods
  1. Saddle point
  2. Dominance method
  3. Oddment method
  4. Algebraic method
  5. Calculus method
  6. Arithmetic method
  7. Matrix method
  8. 2Xn Games
  9. Graphical method
  10. Linear programming method
  11. Bimatrix method

1. Method & Example-1
(Previous example)
4. Algebraic method
(Next method)

2. Example-2





Find Solution of game theory problem using oddment method
Player A\Player BB1B2
A197
A2511


Solution:
1. Saddle point testing
Players
Player `B`
`B_1``B_2`
Player `A``A_1` 9  7 
`A_2` 5  11 


We apply the maximin (minimax) principle to analyze the game.

Player `B`
`B_1``B_2`Row
Minimum
Player `A``A_1` (9)  [7] `[7]`
`A_2` 5  11 `5`
Column
Maximum
`(9)``11`


Select minimum from the maximum of columns
Column MiniMax = (9)

Select maximum from the minimum of rows
Row MaxiMin = [7]

Here, Column MiniMax `!=` Row MaxiMin

`:.` This game has no saddle point.



2. Dominance rule to reduce the size of the payoff matrix
Using dominance property
Player `B`
`B_1``B_2`
Player `A``A_1` 9  7 
`A_2` 5  11 


Also, no course of action dominates the other


Reduced matrix is
Player `B`
`B_1``B_2`
Player `A``A_1` 9  7 
`A_2` 5  11 


Find oddments of individual strategies
1. Find absolute difference between the two values in the first row and put it against second row of the matrix
`|9-7|=2`

2. Find absolute difference between the two values in the second row and put it against first row of the matrix
`|5-11|=6`

3. Find absolute difference between the two values in the first column and put it against second column of the matrix
`|9-5|=4`

4. Find absolute difference between the two values in the second column and put it against first column of the matrix
`|7-11|=4`

So Oddment matrix is
Player `B`
`B_1``B_2`Oddments
Player `A``A_1` 9  7 `|5-11|=6`
`A_2` 5  11 `|9-7|=2`
Oddments`|7-11|=4``|9-5|=4`


Find probabilities of individual strategies
`P(A_1)=(6)/(2+6)=3/4`

`P(A_2)=(2)/(2+6)=1/4`


`P(B_1)=(4)/(4+4)=1/2`

`P(B_2)=(4)/(4+4)=1/2`


Value of game `V=(9*6+5*2)/(2+6)=64/8=8`

Value of game `V=(7*6+11*2)/(2+6)=64/8=8`

Value of game `V=(9*4+7*4)/(4+4)=64/8=8`

Value of game `V=(5*4+11*4)/(4+4)=64/8=8`


This material is intended as a summary. Use your textbook for detail explanation.
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1. Method & Example-1
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4. Algebraic method
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